TS EAMCET · Maths · Differentiation
If \(t\) is a parameter and \(x=t+\frac{1}{t}, y=t-\frac{1}{t}\), then \(\frac{d^2 y}{d x^2}=\)
- A \(\frac{4 t}{\left(t^2-1\right)^2}\)
- B \(\frac{t^2}{\left(t^2-1\right)}\)
- C \(\frac{4 t^3}{\left(t^2-1\right)^3}\)
- D \(\frac{-4 t^3}{\left(t^2-1\right)^3}\)
Answer & Solution
Correct Answer
(D) \(\frac{-4 t^3}{\left(t^2-1\right)^3}\)
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