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TS EAMCET · Maths · Hyperbola

The value of b2 in order that the foci of the hyperbola x2144-y281=125 and the ellipse x216+y2b2=1 coincide is

  1. A 1
  2. B 5
  3. C 7
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(C) 7

Step-by-step Solution

Detailed explanation

Given: hyperbola x2144-y281=125 and the ellipse x216+y2b2=1 Here eccentricity of hyperbola e1=1+81144=1512 So the foci of the hyperbola ±a1e1,0=±3,0 Now foci of ellipse ±a2e2,0=±4e2,0 So according to question 4e2=3 ⇒e2=34  ...i Eccentricity of…