TS EAMCET · Maths · Indefinite Integration
If \(\int\left(1+x-x^{-1}\right) e^{x+x^{-1}} d x=f(x)+c\), then \(f(1)-f(-1)=\)
- A \(e^2-\frac{1}{e^2}\)
- B \(e^2+\frac{1}{e^2}\)
- C \(e+\frac{1}{e}\)
- D \(e-\frac{1}{e}\)
Answer & Solution
Correct Answer
(B) \(e^2+\frac{1}{e^2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{I}=\int\left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} d x \\ & =\int e^{\left(x+\frac{1}{x}\right)} d x+\int x\left(1-\frac{1}{x^2}\right) e^{\left(x+\frac{1}{x}\right)} d x \\ & \text { Using } \int\left[f(x)+x f^{\prime}(x)\right] d x=x f(x)+c \\ &…
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