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TS EAMCET · Maths · Indefinite Integration

If \(\int\left(1+x-x^{-1}\right) e^{x+x^{-1}} d x=f(x)+c\), then \(f(1)-f(-1)=\)

  1. A \(e^2-\frac{1}{e^2}\)
  2. B \(e^2+\frac{1}{e^2}\)
  3. C \(e+\frac{1}{e}\)
  4. D \(e-\frac{1}{e}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(e^2+\frac{1}{e^2}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \mathrm{I}=\int\left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} d x \\ & =\int e^{\left(x+\frac{1}{x}\right)} d x+\int x\left(1-\frac{1}{x^2}\right) e^{\left(x+\frac{1}{x}\right)} d x \\ & \text { Using } \int\left[f(x)+x f^{\prime}(x)\right] d x=x f(x)+c \\ &…

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