TS EAMCET · Maths · Straight Lines
If \(A(-2,1), B(0,-2), C(1,2)\) are the vertices of a triangle \(A B C\), then the perpendicular distance from its circumcentre to the side \(B C\) is
- A \(\frac{7 \sqrt{13}}{22}\)
- B \(\frac{3 \sqrt{17}}{22}\)
- C \(\frac{5 \sqrt{10}}{11}\)
- D \(\frac{\sqrt{2026}}{22}\)
Answer & Solution
Correct Answer
(B) \(\frac{3 \sqrt{17}}{22}\)
Step-by-step Solution
Detailed explanation
Let \((h, k)\) be circumcentre of \(\triangle A B C\) and \(A(-2,1)\), \(B(0,-4, C(1,4)\) are the vertices of \(\triangle A B C\). \( \begin{array}{ll} \therefore \quad & O A=O B=O C \\ & O A=O B \\ & (h+2)^2+(k-1)^2=h^2+(k+2)^2 \\ \Rightarrow \quad & 4 h-6 k+1=0 \end{array} \)…
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