TS EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C, \cot A+\cot B+\cot C=\)
- A \(\frac{a^2+b^2+c^2}{\Delta}\)
- B \(\frac{a+b+c}{4 \Delta}\)
- C \(\frac{a^2+b^2+c^2}{4 \Delta}\)
- D \(\frac{a^2+b^2+c^2}{2 \Delta}\)
Answer & Solution
Correct Answer
(C) \(\frac{a^2+b^2+c^2}{4 \Delta}\)
Step-by-step Solution
Detailed explanation
Let a triangle \(A B C\) of sides \(a, b, c\), having area \(\Delta\) Area \(=\Delta\) \(\frac{1}{2} b c \sin A=\Delta\) \(\ldots({i})\) and \(\quad \frac{1}{2} a c \sin B=\Delta\) \(\ldots({ii})\) and \(\quad \frac{1}{2} a b \sin c=\Delta\) \(\ldots({iii})\) Using cosine rule…
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