TS EAMCET · Maths · Functions
If \(\alpha\) is such a minimum value for which the inverse of \(f(x)=x^2+3 x-3\) exists in \([\alpha, \infty)\) and \(g\) is the inverse of the \(f\), then at \(x=\alpha+\frac{5}{2}, \frac{d g}{d x}\)
- A \(\frac{1}{2}\)
- B \(\frac{1}{3}\)
- C \(\frac{1}{4}\)
- D \(\frac{1}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{5}\)
Step-by-step Solution
Detailed explanation
We have, \(f(x)=x^2+3 x-3\) \(\Rightarrow \quad y=x^2+3 x-3\) \(\Rightarrow \quad y=x^2+3 x-3+\frac{9}{4}-\frac{9}{4}\) \(\Rightarrow y=\left(x+\frac{3}{2}\right)^2-\frac{21}{4}\) \(\Rightarrow \quad y+\frac{21}{4}=\left(x+\frac{3}{2}\right)^2\)…
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