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TS EAMCET · Maths · Limits

If \(f(x)= \begin{cases}\frac{\sin (1+[x])}{[x]}, & \text { for }[x] \neq 0 \ 0, & \text { for }[x]=0\end{cases}\) where \([x]\) denotes the greatest integer not exceeding \(x\), then \(\lim _{x \rightarrow 0^{-}} f(x)\) is equal to

  1. A \(-1\)
  2. B \(0\)
  3. C \(1\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0\)

Step-by-step Solution

Detailed explanation

Given,…