TS EAMCET · Maths · Limits
If \(f(x)= \begin{cases}\frac{\sin (1+[x])}{[x]}, & \text { for }[x] \neq 0 \ 0, & \text { for }[x]=0\end{cases}\) where \([x]\) denotes the greatest integer not exceeding \(x\), then \(\lim _{x \rightarrow 0^{-}} f(x)\) is equal to
- A \(-1\)
- B \(0\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
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