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TS EAMCET · Maths · Functions

If \(\frac{x+1}{x^4(x+2)}=\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x^3}+\frac{D}{x^4}+\frac{E}{x+2}\), then \(B+D+E\) is equal to

  1. A \(A+C\)
  2. B \(A-C\)
  3. C \(2 A+C\)
  4. D \(2 \mathrm{~A}+2 \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(A+C\)

Step-by-step Solution

Detailed explanation

Given, \[ \begin{aligned} & \frac{x+1}{x^4(x+2)}=\frac{A}{x}+\frac{B}{x^2}+\frac{C}{x^3}+\frac{D}{x^4}+\frac{E}{x+2} \\ & \Rightarrow \quad x+1=A x^3(x+2)+B x^2(x+2)+C x(x+2) \\ &+D(x+2)+E x^4 \end{aligned} \] At \(x=-1\),…