TS EAMCET · Maths · Functions
If \(f(x)=\frac{2 x-3}{(x-2)(x-3)}\) is a real valued function then the value that \(f(x)\) does not take is
- A -10
- B 2
- C 1
- D -2
Answer & Solution
Correct Answer
(D) -2
Step-by-step Solution
Detailed explanation
\(f(x)=\frac{2 x-3}{(x-2)(x-3)}\) Let \(y=\frac{2 x-3}{x^2-5 x+6}\) \[ \begin{aligned} & \Rightarrow \mathrm{y}\left(\mathrm{x}^2-5 \mathrm{x}+6\right)-(2 \mathrm{x}-3)=0 \\ & \Rightarrow \mathrm{yx}^2-(5 \mathrm{y}+2) \mathrm{x}+(6 \mathrm{y}+3)=0 \end{aligned} \] for real…
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