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TS EAMCET · Maths · Definite Integration

\(\int_0^3 \frac{3 x+1}{x^2+9} d x\) is equal to :

  1. A \(\log (2 \sqrt{2})+\frac{\pi}{12}\)
  2. B \(\log (2 \sqrt{2})+\frac{\pi}{2}\)
  3. C \(\log (2 \sqrt{2})+\frac{\pi}{6}\)
  4. D \(\log \left(2(\sqrt{2})+\frac{\pi}{3}\right.\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\log (2 \sqrt{2})+\frac{\pi}{12}\)

Step-by-step Solution

Detailed explanation

\(\int_0^3 \frac{3 x+1}{x^2+9} d x=\frac{3}{2} \int_0^3 \frac{2 x}{x^2+9} d x+\int_0^3 \frac{1}{x^2+9} d x\) \(=\frac{3}{2}\left[\log \left(x^2+9\right)\right]_0^3+\frac{1}{3}\left[\tan ^{-1} \frac{x}{3}\right]_0^3\)…