TS EAMCET · Maths · Functions
If \(f(x)=\frac{1}{\sqrt{x+2 \sqrt{2 x-4}}}+\frac{1}{\sqrt{x-2 \sqrt{2 x-4}}}\) for \(x>2\), then \(f(11)\) is equal to
- A \(\frac{7}{6}\)
- B \(\frac{5}{6}\)
- C \(\frac{6}{7}\)
- D \(\frac{5}{7}\)
Answer & Solution
Correct Answer
(C) \(\frac{6}{7}\)
Step-by-step Solution
Detailed explanation
We have, \(f(x)=\frac{1}{\sqrt{x+2 \sqrt{2 x-4}}}+\frac{1}{\sqrt{x-2 \sqrt{2 x-4}}}\) \(f(11)=\frac{1}{\sqrt{11+2 \sqrt{18}}}+\frac{1}{\sqrt{11-2 \sqrt{18}}}\) \(=\frac{1}{\sqrt{11+6 \sqrt{2}}}+\frac{1}{\sqrt{11-6 \sqrt{2}}}\)…
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