TS EAMCET · Maths · Indefinite Integration
If \(\int e^{2 x} f^{\prime}(x) d x=g(x)\), then \(\int\left(e^{2 x} f(x)+e^{2 x} f^{\prime}(x)\right] d x=\)
- A \(\frac{1}{2}\left[e^{2 x} f(x)-g(x)\right]+C\)
- B \(\frac{1}{2}\left[e^{2 x} f(x)+g(x)\right]+C\)
- C \(\frac{1}{2}\left[e^{2 x} f(2 x)+g(x)\right]+C\)
- D \(\frac{1}{2}\left[e^{2 x} f^{\prime}(x)+g(x)\right]+C\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\left[e^{2 x} f(x)-g(x)\right]+C\)
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