TS EAMCET · Maths · Properties of Triangles
\(A+B=C \quad \Rightarrow\) \(\cos ^2 A+\cos ^2 B+\cos ^2 C-2 \cos A \cos B \cos C\) is equal to
- A 1
- B 2
- C 0
- D 3
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Given that, \(A+B=C\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- The nearest approximate value of \(\sqrt{2023}\) isTS EAMCET 2023 Easy
- The area (in square units) bounded by the curves \(|x|=2,|y|=2\) and \(x y \leq \frac{1}{2}\) isTS EAMCET 2020 Easy
- If \(\Delta=a^2-(b-c)^2\), is the area of the \(\triangle A B C\), then \(\tan A\) is equal toTS EAMCET 2010 Easy
- In a \(\triangle A B C\), if \(a \cos ^2 \frac{C}{2}+c \cos ^2 \frac{A}{2}=\frac{3 b}{2}\), thenTS EAMCET 2021 Easy
- If is a matrix and the matrix obtained by replacing the elements of with their corresponding cofactors is , then a possible value of the determinant of isTS EAMCET 2020 Easy
- If \(\cos (A-B)=3 / 5\) and \(\tan A \tan B=2\), then which one of the following is true?TS EAMCET 2007 Medium
More PYQs from TS EAMCET
- What is the approximate angular momentum (in \(\mathrm{J} \mathrm{s}\) ) of electron in hydrogen atom in its ground state? \[ \left(\mathrm{h}=6.625 \times 10^{-34} \mathrm{Js}\right) \]TS EAMCET 2023 Medium
- If the latus rectum through one of the foci of a hyperbola \(\frac{x^2}{9}-\frac{y^2}{b^2}=1\) subtends a right angle at the farther vertex of the hyperbola, then \(b^2=\)TS EAMCET 2025 Medium
- Match the following
The correct match isColumn-1
Reaction of carbonyl
compound withColumn-2
ProductA) Hydroxylamine I) Hydrazone B) Alcohol II) Schiff's base (Substituted imine) C) Hydrazine III) Oxime D) Amine IV) Ketal TS EAMCET 2021 Medium - Gelly is a colloidal solution ofTS EAMCET 2012 Easy
- Round the number 234555359 to 3 significant figures.TS EAMCET 2022 Easy
- Given that \(a, b \in\{0,1,2, \ldots, 9\}\) with \(a+b \neq 0\) and that \(\left(a+\frac{b}{10}\right)^x=\left(\frac{a}{10}+\frac{b}{100}\right)^y=1000 . \quad\) Then, \(\frac{1}{x}-\frac{1}{y}\) is equal toTS EAMCET 2008 Hard