TS EAMCET · Maths · Quadratic Equation
If \(\alpha_1, \alpha_2\) are the roots of \(x^2+a x+1=0\) and \(\alpha_3, \alpha_4\) are the roots of \(x^2+b x+1=0\), then \(\left(\alpha_1+\alpha_3\right)\left(\alpha_2+\alpha_3\right)\left(\alpha_1+\alpha_4\right)\left(\alpha_2+\alpha_4\right)=\)
- A \(3 a^2-b^2\)
- B \(a^2-3 b^2\)
- C \((a-b)^2\)
- D \((b+a)^2\)
Answer & Solution
Correct Answer
(D) \((b+a)^2\)
Step-by-step Solution
Detailed explanation
Since, \(\alpha_1, \alpha_2\) are roots of \(x^2+a x+1=0\) and \(\alpha_3, \alpha_4\) are roots of \(x^2+b x+1=0\), so…
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