TS EAMCET · Chemistry · Solutions
An aqueous dilute solution containing non-volatile solute boils at \(100.52^{\circ} \mathrm{C}\). What is the molality of solution? \(\left(K_b=0.52 \mathrm{~kg} \mathrm{~mol}^{-1} \mathrm{~K}\right.\), boiling temperature of water \(=100^{\circ} \mathrm{C}\) )
- A \(0.1 \mathrm{~m}\)
- B \(0.01 \mathrm{~m}\)
- C \(0.001 \mathrm{~m}\)
- D \(1.0 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(0.1 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\Delta T_b=K_b \cdot m\) \[ T_b-T_b^{\circ}=K_b \cdot m \] where, \(K_b=\) molal elevation constant \(m=\) molality \[ \begin{aligned} (100.052-100.00) & =(0.52)(m) \\ 0.052 & =0.52 \times m \\ m & =0.1 \end{aligned} \]
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