TS EAMCET · Maths · Probability
If a random variable \(X\) has the following probability distribution, then its variance is \(\begin{array}{|l|c|c|c|c|} \hline X=x & 1 & 3 & 5 & 2 \ \hline P(X=x) & 3 K^2 & K & K^2 & 2 K \ \hline \end{array}\)
- A \(\frac{9}{4}\)
- B \(\frac{25}{8}\)
- C \(\frac{27}{16}\)
- D \(\frac{15}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{15}{16}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & 3 k^2+k+k^2+2 k=1 \\ \Rightarrow & (4 k-1)(k+1)=0 \Rightarrow k=\frac{1}{4}(k \neq-1)\end{aligned}\)…
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