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TS EAMCET · Maths · Straight Lines

If a line L passing through the point \(\mathrm{A}(-2,4)\) makes an angle of \(60^{\circ}\) with the positive direction of X -axis in anti-clockwise direction and \(\mathrm{B}(p, q)\) lying in the \(3^{\text {rd }}\) quadrant is a point on L at the distance of 6 units from the point A, then \(\sqrt{p^2+q^2-8 q}=\)

  1. A 6
  2. B 7
  3. C 8
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(A) 6

Step-by-step Solution

Detailed explanation

\(p = -2 - 6 \cos 60^{\circ} = -2 - 6(1/2) = -5\) \(q = 4 - 6 \sin 60^{\circ} = 4 - 6(\sqrt{3}/2) = 4 - 3\sqrt{3}\) \(\sqrt{p^2 + q^2 - 8q} = \sqrt{p^2 + (q-4)^2 - 16}\) \(= \sqrt{(-5)^2 + (4 - 3\sqrt{3} - 4)^2 - 16}\) \(= \sqrt{25 + (-3\sqrt{3})^2 - 16}\)…