TS EAMCET · Maths · Vector Algebra
If \(\bar{a}=\bar{i}+\sqrt{11} \bar{j}-2 \bar{k}\) and \(\bar{b}=\bar{i}+\sqrt{11} \bar{j}-10 \bar{k}\) are two vectors then the component of \(\bar{b}\) perpendicular to \(\bar{a}\) is
- A \(3 \bar{i}-\sqrt{11} \bar{j}-4 \bar{k}\)
- B \(\bar{i}-\sqrt{11} \bar{j}-5 \bar{k}\)
- C \(-(\bar{i}+\sqrt{11} \bar{j}+6 \bar{k})\)
- D \(-5 \bar{i}+\sqrt{11} \bar{j}+3 \bar{k}\)
Answer & Solution
Correct Answer
(C) \(-(\bar{i}+\sqrt{11} \bar{j}+6 \bar{k})\)
Step-by-step Solution
Detailed explanation
\(\bar{a} \cdot \bar{b} = (1)(1) + (\sqrt{11})(\sqrt{11}) + (-2)(-10) = 1 + 11 + 20 = 32\) \(|\bar{a}|^2 = (1)^2 + (\sqrt{11})^2 + (-2)^2 = 1 + 11 + 4 = 16\)…
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