TS EAMCET · Maths · Trigonometric Ratios & Identities
If \(A+B+C=\frac{\pi}{3}\) then \(\sin \left(\frac{\pi-6 A}{6}\right)+\sin \left(\frac{\pi-6 B}{6}\right)+\sin C=\)
- A \(-1+4 \cos \left(\frac{\pi-6 A}{12}\right) \cos \left(\frac{\pi-6 B}{12}\right) \sin \frac{C}{2}\)
- B \(4 \sin \left(\frac{\pi+6 A}{12}\right) \sin \left(\frac{\pi+6 B}{12}\right) \cos \frac{C}{2}\)
- C \(1-4 \cos \left(\frac{\pi-6 A}{12}\right) \cos \left(\frac{\pi-6 B}{12}\right) \cos \frac{\pi-6 C}{12}\)
- D \(4 \cos \left(\frac{\pi-6 A}{12}\right) \cos \left(\frac{\pi-6 B}{12}\right) \sin \frac{C}{2}\)
Answer & Solution
Correct Answer
(D) \(4 \cos \left(\frac{\pi-6 A}{12}\right) \cos \left(\frac{\pi-6 B}{12}\right) \sin \frac{C}{2}\)
Step-by-step Solution
Detailed explanation
Given, \(A+B+C=\frac{\pi}{3}\)…
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