TS EAMCET · Maths · Probability
In a non-leap year, the probability of getting 53 Sunday or 53 Tuesday or 53 Thursday is
- A \(\frac {1}{7}\)
- B \(\frac {2}{7}\)
- C \(\frac {3}{7}\)
- D \(\frac {4}{7}\)
Answer & Solution
Correct Answer
(C) \(\frac {3}{7}\)
Step-by-step Solution
Detailed explanation
In non-leap year, there are 365 days i.e. 52 complete weeks and \(1\) extra day. That day can be any of 7 days. \(\therefore \quad P(53 \text { Sunday })=P(\text { Last } 1 \text { day Sunday })=\frac{1}{7}\) Similarly, \(P(53\) Tuesday \()=\frac{1}{7}\)…
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