TS EAMCET · Maths · Quadratic Equation
If \(\sqrt{9 x^2+6 x+1} < (2-x)\), then:
- A \(x \in\left(-\frac{3}{2}, \frac{1}{4}\right)\)
- B \(x \in\left(-\frac{3}{2}, \frac{1}{4}\right]\)
- C \(x \in\left[-\frac{3}{2}, \frac{1}{4}\right)\)
- D \(x < \frac{1}{4}\)
Answer & Solution
Correct Answer
(A) \(x \in\left(-\frac{3}{2}, \frac{1}{4}\right)\)
Step-by-step Solution
Detailed explanation
\(\sqrt{9 x^2+6 x+1} -\frac{3}{2}\) \(\therefore \quad x \in\left(-\frac{3}{2}, \frac{1}{4}\right)\)
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