TS EAMCET · Maths · Circle
The length of the common chord of the circles \(x^2+y^2-6 x-4 y+9=0\) and \(x^2+y^2-8 x-6 y+23=0\) is
- A \(\sqrt{2}\)
- B \(2\)
- C \(2 \sqrt{2}\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(2 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Equation of common chord of given circles \(=2 x+2 y-14=0\) Now, radius and centre of circle \(x^2+y^2-6 x-4 y+9=0\) are respectively 2 and \((3,2)\) length of perpendicular from \((3,-2)\) to (i) is…
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