TS EAMCET · Maths · Ellipse
If \(\mathrm{P}\left(\frac{1}{2}, 4\right)\) and \(\mathrm{Q}\) are the ends of a focal chord of the parabola \(y^2=32 x\) and \(\mathrm{S}\) is the focus of the parabola then \(\mathrm{SQ}=\)
- A \(\frac{17}{2}\)
- B \(\frac{\sqrt{65}}{2}\)
- C 136
- D \(\frac{289}{2}\)
Answer & Solution
Correct Answer
(C) 136
Step-by-step Solution
Detailed explanation
Given parabola \(y^2=32 x\) \[ \begin{aligned} & \Rightarrow \mathrm{a}=8, \mathrm{~S}=(8,0) \\ & \text { and } \mathrm{P}=\left(\frac{1}{2}, 4\right) \Rightarrow \mathrm{Q}=(128,-64) \\ & \text { Now } \mathrm{SQ}=\sqrt{(128-8)^2+(-64)^2}=136 \end{aligned} \]
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