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TS EAMCET · Maths · Ellipse

If \(4 x+2 y+n=0\) is a normal to the ellipse \(\frac{x^2}{36}+\frac{y^2}{16}=1\), then \(n=\)

  1. A \(\pm \frac{9}{4}\)
  2. B \(\pm \frac{9}{\sqrt{10}}\)
  3. C \(\pm \frac{5}{4}\)
  4. D \(\pm 8\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\pm 8\)

Step-by-step Solution

Detailed explanation

\[ \begin{aligned} & \text 4 x+2 y+n=0 \Rightarrow y=-2 x-\frac{n}{2} \\ & \Rightarrow \frac{x^2}{36}+\frac{y^2}{16}=1 \end{aligned} \] If \(y=m x+c\) is normal to ellipse…