TS EAMCET · Maths · Permutation Combination
are three particular speakers among the speakers of a meeting. The number of ways of arranging all the speakers on the dias in a row so that all the three speakers do not sit together is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
Given, a,b,c are three particular speakers among the 10 speakers of a meeting. So number of ways of arranging 10 speaker will be 10! Now assuming all three a, b & c are sitting together, so number of ways of arranging them will be 3×8! Now the number of…
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