TS EAMCET · Maths · Quadratic Equation
The roots of the equation \(x^3-3 x^2+3 x+7=0\) are \(\alpha\), \(\beta, \gamma\) and \(\omega, \omega^2\) are complex cube roots of unity. If the terms containing \(x^2\) and \(x\) are missing in the transformed equation when each one of these roots is decreased by \(h\), then \(\frac{\alpha-h}{\beta-h}+\frac{\beta-h}{\gamma-h}+\frac{\gamma-\mathrm{h}}{\alpha-\mathrm{h}}=\)
- A \(\frac{3}{w^2}\)
- B \(3 \omega\)
- C 0
- D \(3 \omega^2\)
Answer & Solution
Correct Answer
(D) \(3 \omega^2\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & x^3-3 x^2+3 x+7=0 \Rightarrow(x+1)\left(x^2-4 x+7\right)=0 \\ \Rightarrow & x=-1,1-2 \omega, 1-2 \omega^2\end{aligned}\) Equation of roots \(\alpha-h, \beta-h, \gamma-h\) is…
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