TS EAMCET · Maths · Circle
If \(2 x+y=0\) is the equation of a chord of the circle \(x^2+y^2-2 x-6 y+3=0\), then the circle with this chord as diameter passes through the point
- A (-3,2)
- B (5,-2)
- C (-5,3)
- D (-2,1)
Answer & Solution
Correct Answer
(D) (-2,1)
Step-by-step Solution
Detailed explanation
\(2 x+y=0\) is equation of chord of circle, \(\begin{aligned} x^2+y^2-2 x-6 y+3 & =0 \\ \therefore \quad x^2+y^2-2 x-6 y+3+\lambda(2 x+y) & =0 \\ x^2+y^2+2 x(\lambda-1)+y(\lambda-6)+3 & =0 \end{aligned}\) \(2 x+y=0\) is also diameter of the required circle \(\because\) Centre of…
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