TS EAMCET · Maths · Matrices
If \(x^2+y^2+z^2 \neq 0, \quad x=c y+b z, \quad y=a z+c x\) and \(z=b x+a y\), then \(a^2+b^2+c^2+2 a b c\) is equal to
- A \(1\)
- B \(2\)
- C \(a+b+c\)
- D \(a b+b c+c a\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} x-c y-b z & =0 \\ -c x+y-a z & =0 \\ -b x-a y+z & =0 \end{aligned} \] Eliminating \(x, y, z\), we get…
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