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TS EAMCET · Maths · Matrices

If \(x^2+y^2+z^2 \neq 0, \quad x=c y+b z, \quad y=a z+c x\) and \(z=b x+a y\), then \(a^2+b^2+c^2+2 a b c\) is equal to

  1. A \(1\)
  2. B \(2\)
  3. C \(a+b+c\)
  4. D \(a b+b c+c a\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

We have, \[ \begin{aligned} x-c y-b z & =0 \\ -c x+y-a z & =0 \\ -b x-a y+z & =0 \end{aligned} \] Eliminating \(x, y, z\), we get…