TS EAMCET · Maths · Properties of Triangles
If \(\mathrm{S}\) is the circumcentre of a triangle ABC, \(a=5, b=6\), \(c=9\) and \(\mathrm{SB}=\frac{27}{4 \sqrt{2}}\) then \(\sin 2 \mathrm{C}=\)
- A \(\frac{4 \sqrt{2}}{9}\)
- B \(\frac{4 \sqrt{2}}{27}\)
- C \(\frac{-4 \sqrt{2}}{27}\)
- D \(\frac{-4 \sqrt{2}}{9}\)
Answer & Solution
Correct Answer
(D) \(\frac{-4 \sqrt{2}}{9}\)
Step-by-step Solution
Detailed explanation
Given \(a=5, b=6, c=9, \mathrm{R}=\frac{27}{4 \sqrt{2}}\) Hence, \(\sin 2 c=2 \sin c \cos c\)…
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