TS EAMCET · Maths · Indefinite Integration
If \(\frac{2 x+1}{(x-1)^2\left(x^2+1\right)}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{C x+D}{x^2+1}\), then \(A+B+C+D=\)
- A 1
- B 2
- C \(\frac{3}{4}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
If \(\frac{2 x+1}{(x-1)^2\left(x^2+1\right)}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{C x+D}{x^2+1}\) \(\Rightarrow \quad 2 x+1=A(x-1)\left(x^2+1\right)+B\left(x^2+1\right)\) \(+(C x+D)(x-1)^2\) \(\Rightarrow \quad 2 x+1=x^3(A+C)+x^2(-A+B-2 C+D)\) \(+x(A+C-2 D)+(-A+B+D)\) On…
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