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TS EAMCET · Maths · Indefinite Integration

If \(\frac{2 x+1}{(x-1)^2\left(x^2+1\right)}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{C x+D}{x^2+1}\), then \(A+B+C+D=\)

  1. A 1
  2. B 2
  3. C \(\frac{3}{4}\)
  4. D \(\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

If \(\frac{2 x+1}{(x-1)^2\left(x^2+1\right)}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{C x+D}{x^2+1}\) \(\Rightarrow \quad 2 x+1=A(x-1)\left(x^2+1\right)+B\left(x^2+1\right)\) \(+(C x+D)(x-1)^2\) \(\Rightarrow \quad 2 x+1=x^3(A+C)+x^2(-A+B-2 C+D)\) \(+x(A+C-2 D)+(-A+B+D)\) On…