TS EAMCET · Chemistry · Solutions
At \(300 \mathrm{~K}\), the osmotic pressure of a decinormal solution of sodium chloride is \(4.82 \mathrm{~atm}\). The degree of dissociation of sodium chloride is \(\mathrm{x} \times 10^{-2}\). The value of \(x\) is \(\left(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{moi}^{-1}\right)\)
- A \(90\)
- B \(96\)
- C \(93\)
- D \(88\)
Answer & Solution
Correct Answer
(B) \(96\)
Step-by-step Solution
Detailed explanation
We have, \(\pi=4.82 \mathrm{~atm}, \mathrm{C}=0.1 \mathrm{~N}\), \(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} / \mathrm{mol} \mathrm{K}\). \(\pi=\mathrm{i}\) CRT \[ \Rightarrow \mathrm{i}=\frac{\pi}{\mathrm{CRT}}=\frac{4.82}{0.1 \times 0.082 \times 300}=1.96 \] Now,…
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