TS EAMCET · Maths · Probability
If three dice are thrown at a time, then the probability of getting the sum of the numbers on them as a prime number is
- A \(\frac{3}{8}\)
- B \(\frac{73}{216}\)
- C \(\frac{4}{27}\)
- D \(\frac{5}{54}\)
Answer & Solution
Correct Answer
(B) \(\frac{73}{216}\)
Step-by-step Solution
Detailed explanation
Total outcomes \( = 6^3 = 216 \). Prime sums for three dice: 3, 5, 7, 11, 13, 17. Number of ways to get prime sums: \( P(3) = 1 \) (1,1,1) \( P(5) = 6 \) (1,1,3 perm.; 1,2,2 perm.) \( P(7) = 15 \) (1,1,5 perm.; 1,2,4 perm.; 1,3,3 perm.; 2,2,3 perm.) \( P(11) = 27 \) (1,4,6…
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