TS EAMCET · Maths · Pair of Lines
If the lines joining the origin to the points of intersection of the line \(x+y=k\) and the curve \(x^2+y^2-2 x-4 y+2=0\) are at right angles then the sum of all the possible values of \(k\) is
- A 0
- B 1
- C 3
- D 5
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
Given curve \(x^2+y^2-2 x-4 y+2=0\) and line \(x+y=k\) \[ \begin{gathered} x+y=k \\ \frac{x+y}{k}=1 \end{gathered} \] Now, Homogenising (i) and the given curve. Take, \(x^2+y^2-2(x+2 y)(1)+2(1)^2=0\)…
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