TS EAMCET · Maths · Trigonometric Ratios & Identities
If \(1^{\circ}=\alpha\) radians, then the approximate value of \(\cos \left(60^{\circ} 1^{\prime}\right)\) is
- A \(\frac{1}{2}+\frac{\alpha \sqrt{3}}{120}\)
- B \(\frac{1}{2}-\frac{\alpha}{120}\)
- C \(\frac{1}{2}-\frac{\alpha \sqrt{3}}{120}\)
- D \(\frac{1}{2}+\frac{\alpha}{120}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}-\frac{\alpha \sqrt{3}}{120}\)
Step-by-step Solution
Detailed explanation
\(\therefore \cos \left(60^{\circ} 1^{\prime}\right)=\frac{1}{2}-\frac{\alpha \sqrt{3}}{120}\)
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