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TS EAMCET · Maths · Quadratic Equation

The roots of the equation \(x^4+x^3-4 x^2+x+1=0\) are diminished by \(h\) so that the transformed equation does not contain \(\mathrm{x}^2\) term. If the values of such \(\mathrm{h}\) are \(\alpha\) and \(\beta\), then \(12(\alpha-\beta)^2=\)

  1. A \(35\)
  2. B \(25\)
  3. C \(105\)
  4. D \(115\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(35\)

Step-by-step Solution

Detailed explanation

\(x^4+x^3-4 x^2+x+1=0\) \[ =(x-1)^2\left(x^2+3 x+1\right)=0 \] \(\therefore\) roots are \(1,1, \frac{-3 \pm \sqrt{5}}{2}\) Let \(\alpha=1, \beta=1, \gamma=\frac{-3+\sqrt{5}}{2}, \delta=\frac{-3-\sqrt{5}}{2}\) Coefficient of \(x^2=\Sigma \alpha \beta\)…
From TS EAMCET
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