TS EAMCET · Maths · Determinants
If \(A=\left[\begin{array}{lll}1 & 5 & 2 \\ 4 & 1 & 3 \\ 2 & 6 & 3\end{array}\right]\), then \(\left|(\operatorname{Adj} A)^{-1}\right|=\)
- A -1
- B 1
- C 4
- D -4
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
\( \det A = 1(1 \cdot 3 - 3 \cdot 6) - 5(4 \cdot 3 - 3 \cdot 2) + 2(4 \cdot 6 - 1 \cdot 2) = 1(3 - 18) - 5(12 - 6) + 2(24 - 2) \) \( \det A = 1(-15) - 5(6) + 2(22) = -15 - 30 + 44 = -1 \)…
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