TS EAMCET · Maths · Straight Lines
\(C_1\) and \(C_2\) are the external and internal centres of similitude of the circles \(x^2+y^2-2 x+4 y+1=0\) and \(x^2+y^2+4 x-6 y+12=0\). If the radius of the circle having \(C_1 C_2\) as its diameters is \(r\), then \(\frac{9}{2} r=\)
- A \(\sqrt{15}\)
- B \(3 \sqrt{15}\)
- C \(2 \sqrt{34}\)
- D \(3 \sqrt{34}\)
Answer & Solution
Correct Answer
(D) \(3 \sqrt{34}\)
Step-by-step Solution
Detailed explanation
\(C_1\) and \(C_2\) are external and internal similitude of the circle \(x^2+y^2-2 x+4 y+1=0\) and \(\quad x^2+y^2+4 x-6 y+12=0\) Centre of circle \(x^2+y^2-2 x+4 y+1=0\) is \((1,-2), r_1=2\) Centre of circle \(x^2+y^2+4 x-6 y+4=0\) \((-2,3), r_2=1\) Coordinate of…
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