TS EAMCET · Maths · Trigonometric Ratios & Identities
\(\sinh (\log (3+\sqrt{8}))=\)
- A \(3^{\frac{3}{2}}\)
- B \(2^{\frac{3}{2}}\)
- C \(8^{\frac{2}{3}}\)
- D \(3^{\frac{1}{2}}\)
Answer & Solution
Correct Answer
(B) \(2^{\frac{3}{2}}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \quad \sin h(\log (3+\sqrt{8})) \\ & =\sin h(\log (3+2 \sqrt{2}))=\sin h\left\{\log (\sqrt{2}+1)^2\right\} \\ & \because \sin h x=\frac{e^x-e^{-x}}{2} \\ & \sin h\left(\log (\sqrt{2}+1)^2\right)=\frac{e^{\log (\sqrt{2}+1)^2}-e^{-\log (\sqrt{2}+1)^2}}{2} \\ &…
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