TS EAMCET · Maths · Basic of Mathematics
If \(a, b, c, \neq 0\) and belong to the set to \(\{0,1,2\), \(3 \ldots \ldots, 9\}\), then \(\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)\) is equal to
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(D) 4
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right) \\ & =\log _{10}\left(\frac{a+10 b+10^2 c}{\frac{1}{10^4}\left(a+10 b+10^2 c\right)}\right)=\log _{10} 10^4=4\end{aligned}\)
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