TS EAMCET · Maths · Matrices
For a square matrix \(B\) of order 3, if \(B^T=B^{-1}\) and \(|B|=1\), then \(|B-I|=\)
- A 1
- B -1
- C \(2|B|\)
- D \(\left|B^T\right|-1\)
Answer & Solution
Correct Answer
(D) \(\left|B^T\right|-1\)
Step-by-step Solution
Detailed explanation
Given, \(B^T=B^{-1} \Rightarrow B B^{-1}=I\) \(\therefore B\) is a orthogonally,…
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