TS EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{x \tan 4 x-2 x \tan 2 x}{(1-\cos 4 x)^2}=\)
- A \(\frac{1}{8}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{2}\)
- D 1
Answer & Solution
Correct Answer
(B) \(\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0} \frac{x \tan 4 x-2 x \tan 2 x}{(1-\cos 4 x)^2}\) \(=\lim _{x \rightarrow 0} \frac{x\left[(4 x)+\frac{1}{3}(4 x)^3+\frac{2}{15}(4 x)^5+\ldots\right] -2 x\left[(2 x)+\frac{1}{3}(2 x)^3+\frac{2}{15}(2 x)^5+\ldots\right]}{\left(2 \sin ^2 2 x\right)^2}\)…
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