TS EAMCET · Maths · Hyperbola
Equation of one of the tangents passing through \((2,8)\) to the hyperbola \(5 x^2-y^2=5\) is
- A \(3 x+y-14=0\)
- B \(3 x-y+2=0\)
- C \(x+y+3=0\)
- D \(x-y+6=0\)
Answer & Solution
Correct Answer
(B) \(3 x-y+2=0\)
Step-by-step Solution
Detailed explanation
Given hyperbola is \(5 x^2-y^2=5\) or It can be rewritten as \(\frac{x^2}{1}-\frac{y^2}{5}=1\) Here, \(\therefore\) Equation of tangent is \(\begin{aligned} & y=m x \pm \sqrt{a^2 m^2-b^2} \\ & y=m x \pm \sqrt{1 m^2-5}\end{aligned}\) But point \((2,8)\) lies on it.…
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