TS EAMCET · Maths · Parabola
The equation of the parabola with \(x+2 y=1\) as directrix and \((1,0)\) as focus is
- A \(4 x^2-4 x y+y^2-8 x+4 y+4=0\)
- B \(4 x^2-4 x y+y^2-4 x+4 y+4=0\)
- C \(4 x^2-4 x y+y^2+8 x+4 y+4=0\)
- D \(x^2-4 x y+y^2-8 x+4 y+4=0\)
Answer & Solution
Correct Answer
(A) \(4 x^2-4 x y+y^2-8 x+4 y+4=0\)
Step-by-step Solution
Detailed explanation
\(D: x+2 y=1\) \(S(1,0)\) Let locus of point on parabola is \(P(x, y)\). \(\begin{aligned} & P S=P M \\ & \frac{x+2 y-1}{\sqrt{1^2+2^2}}=\sqrt{(x-1)^2+y^2} \end{aligned}\)…
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