TS EAMCET · Maths · Indefinite Integration
\(\int e^{-2 x}\left(\tan 2 x-2 \sec ^2 2 x \tan 2 x\right) d x=\)
- A \(e^{-2 x} \tan 2 x+c\)
- B \(-\frac{e^{-2 x}}{2}\left[\sec ^2 2 x+\tan 2 x\right]+c\)
- C \(-\frac{e^{-2 x}}{2}\left[\tan 2 x-\sec ^2 2 x\right]+c\)
- D \(e^{-2 x} \sec ^2 2 x+c\)
Answer & Solution
Correct Answer
(B) \(-\frac{e^{-2 x}}{2}\left[\sec ^2 2 x+\tan 2 x\right]+c\)
Step-by-step Solution
Detailed explanation
Let \(-2 x=t \Rightarrow-2 d x=d t\)…
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