TS EAMCET · Maths · Matrices
Let \(\mathrm{A}\) be a matrix such that \(\mathrm{AB}\) is a scalar matrix where \(B=\left[\begin{array}{ll}1 & 2 \\ 0 & 3\end{array}\right]\) and \(\operatorname{det}(3 A)=27\). Then \(3 A^{-1}+A^2=\)
- A \(\left[\begin{array}{cc}4 & -6 \\ 0 & 2\end{array}\right]\)
- B \(\left[\begin{array}{cc}9 & -4 \\ 0 & 3\end{array}\right]\)
- C \(\left[\begin{array}{cc}10 & -6 \\ 0 & 2\end{array}\right]\)
- D \(\left[\begin{array}{cc}10 & -6 \\ 0 & 4\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{cc}10 & -6 \\ 0 & 4\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right] \\ & A B=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\left[\begin{array}{ll}1 & 2 \\ 0 & 3\end{array}\right]=\left[\begin{array}{ll}a & 2 a+3 b \\ c & 2 c+3…
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