TS EAMCET · Maths · Probability
Two cards are drawn from a pack of 52 playing cards one after the other. If \(p_1\) is the probability of getting a queen in the first draw and a diamond card in the second draw when the first card drawn is replaced and \(p_2\) is the probability of the same event when the first card drawn is not replaced. Then \(\frac{\mathrm{p}_1}{\mathrm{p}_2}=\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Case 1: with replacement \(\mathrm{P}_1=\mathrm{P}\) (First queen and second diamond \()\) \[ =\frac{4}{52} \times \frac{13}{52}=\frac{1}{52} \] Case 2 : without replacement \(\mathrm{P}_2=\mathrm{P}\) (First queen and second diamond) \(={ }^2 \mathrm{P}(\) First diamond queen…
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