TS EAMCET · Maths · Probability
Bag 'P' contains 3 white, 2 red, 5 blue balls and bag 'Q' contains 2 white, 3 red, 5 blue balls. A ball is chosen at random from ' P ' and is placed in ' Q '. If a ball is chosen from bag ' \(Q\) ' at random, then the probability that it is a red ball is
- A \(\frac{9}{50}\)
- B \(\frac{13}{45}\)
- C \(\frac{16}{55}\)
- D \(\frac{12}{35}\)
Answer & Solution
Correct Answer
(C) \(\frac{16}{55}\)
Step-by-step Solution
Detailed explanation
Using multiplication theorem of probability. Required probability \(\begin{aligned} & =\frac{3}{10} \times \frac{3}{11}+\frac{2}{10} \times \frac{4}{11}+\frac{5}{10} \times \frac{3}{11} \\ & =\frac{9+8+15}{110}=\frac{32}{110}=\frac{16}{55} . \end{aligned}\)
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