TS EAMCET · Maths · Area Under Curves
Area of the triangle bounded by the lines given by the equations \(12 x^2-20 x y+7 y^2=0\) and \(x+y-1=0\) is
- A \(\frac{8}{29}\)
- B \(\frac{8}{39}\)
- C \(\frac{4}{29}\)
- D \(\frac{4}{39}\)
Answer & Solution
Correct Answer
(D) \(\frac{4}{39}\)
Step-by-step Solution
Detailed explanation
\(12 x^2-20 x y+7 y^2=0\) \(\begin{aligned} & \Rightarrow 12 x^2-14 x y-6 x y+7 y^2=0 \\ & \Rightarrow 2 x(6 x-7 y)-y(6 x-7 y)=0 \\ & \Rightarrow(2 x-y)(6 x-7 y)=0 \end{aligned}\) Sides are \(y=\frac{6 x}{7}, y=2 x\) Solving the above equations to get vertices…
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