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TS EAMCET · Maths · Vector Algebra

\(\vec{a}\) is a vector perpendicular to the plane containing non zero vectors \(\vec{b}\) and \(\vec{c}\). If \(\vec{a}, \vec{b}, \vec{c}\) are such that \(|\vec{a}+\vec{b}+\vec{c}|=\sqrt{|\vec{a}|^2+|\vec{b}|^2+|\vec{c}|^2}\), then \(|(\vec{a} \times \vec{b}) \cdot \vec{c}|+|(\vec{a} \times \vec{b}) \times \vec{c}|=\)

  1. A \(|\vec{a}|+|\vec{b}|+|\vec{c}|\)
  2. B \(|\vec{a}||\vec{b}||\vec{c}|\)
  3. C \(|\vec{a}|^2+|\vec{b}|^2+|\vec{c}|^2\)
  4. D \(|\vec{a}|^2|\vec{b}|^2|\vec{c}|^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(|\vec{a}||\vec{b}||\vec{c}|\)

Step-by-step Solution

Detailed explanation

\(\vec{a} \perp \vec{b}\) and \(\vec{a} \perp \vec{c} \Rightarrow \vec{a} \vec{b}=0, \vec{a} \cdot \vec{c}=0\) and \(|\vec{a}+\vec{b}+\vec{c}|=\sqrt{|\vec{a}|^2+|\vec{b}|^2+|\vec{c}|^2}\). Squaring both sides…