TS EAMCET · Maths · Vector Algebra
Let \(\mathrm{L}\) be a line passing through a point \(\mathrm{A}\) and parallel to the vector \(2 \hat{i}+\hat{j}-2 \hat{k}\). Let \(-7 \hat{i}-5 \hat{j}+11 \hat{k}\) be the position vector of a point \(\mathrm{P}\) on \(\mathrm{L}\) such that \(|\overline{\mathrm{AP}}|=12\). Then the position vector of A can be
- A \(\hat{i}+\hat{j}+3 \hat{k}\)
- B \(15 \hat{i}+9 \hat{j}-19 \hat{k}\)
- C \(-\hat{i}-\hat{j}+3 \hat{k}\)
- D \(-15 \hat{i}-9 \hat{j}+19 \hat{k}\)
Answer & Solution
Correct Answer
(D) \(-15 \hat{i}-9 \hat{j}+19 \hat{k}\)
Step-by-step Solution
Detailed explanation
(d) Let the point \(\mathrm{A}\) is \((\alpha, \beta, \gamma)\) and line \(\mathrm{L}\) parallel to the vector Required line \(\mathrm{L}=\vec{r}=(\alpha \hat{i}+\beta \hat{j}+\gamma \hat{k})+\lambda(2 \hat{i}+\hat{j}-2 \hat{k})\) Here,…
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